By Giles J.R.

ISBN-10: 0521350514

ISBN-13: 9780521350518

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That is for every x ∈ K 1 ∪ K 2 , ∇x − T x∇ = d. Theorem 13 [8] Let (A, B) be a nonempty weakly compact convex pair in a strictly convex Banach space. Let T : A ∪ B → A ∪ B be a relatively nonexpansive 22 P. Veeramani and S. Rajesh map such that T (A) ⊆ A and T (B) ⊆ B. Suppose (A, B) has proximal normal structure, then there exists (x, y) ∈ A × B such that x = T x, y = T y, and ∇T x − T y∇ = ∇x − y∇ = dist(A, B). Proof It is easy to see that T (A0 ) ⊆ A0 and T (B0 ) ⊆ B0 , where (A0 , B0 ) is the proximal pair obtained from the pair (A, B).

Then x1 ∈ M1 , x2 ∈ M2 and ∇x1 − x2 ∇ = d and the pair (M1 , M2 ) is a nonempty closed convex subset of (K 1 , K 2 ) such that dist(M1 , M2 ) = d. Since K 1 = co(T (K 2 )), for x ∈ M1 , r T x (K 1 ) = sup{∇T x − y∇ : y ∈ K 1 } = sup{∇T x − T z∇ : z ∈ K 2 } ≤ sup{∇x − z∇ : z ∈ K 2 } ≤ R. Thus T x ∈ M2 , if x ∈ M1 . Hence T (M1 ) ⊆ M2 and in a similar way it follows that T (M2 ) ⊆ M1 . Since (K 1 , K 2 ) is minimal, (M1 , M2 ) = (K 1 , K 2 ). Now δ(K 1 , K 2 ) = sup r x (K 2 ) = sup r y (K 1 ). But for (x, y) ∈ M1 × x∈M1 =K 1 y∈M2 =K 2 M2 , r x (K 2 ) ≤ R and r y (K 1 ) ≤ R.

Studia Math. 171, 283–293 (2005) 9. : Existence and convergence of best proximity points. J. Math. Anal. Appl. 323, 1001–1006 (2006) 10. : On best proximity pair solutions with applications to differential equations. J. Indian Math. Soc. ) 2007. Special volume on the occasion of the centenary year of IMS (1907–2007), 51–62 (2008) 11. : A new approach to relatively nonexpansive mappings. Proc. Am. Math. Soc. 136, 1987–1995 (2008) 12. : On best proximity points in metric and Banach spaces. Can. J.

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